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Seung Cheol Lee
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Apr 5, 2009 - 9:24 PM
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I found the short key error in menu. The short key is Alt + Key. I made the test menu below. ========================== &Test &1.Test ----> Alt + 1 &2.Test -----> Alt + 2 &3.Test -----> Alt + 3 &0.Test -----> Alt + 0 ========================== &1.Test, &2.Test and &3.Test operated well. But &0.Test didn’t opeate. It was impossible to use Alt+0 in menu. Could you check the error. Prof-UIS Ver. : 2.84 OS : Windows Vista Lanuage : Korean IDE : VS2005
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Technical Support
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Apr 6, 2009 - 10:11 AM
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Thank you for reporting this issue. Here is how the beginning of the CExtPopupMenuWnd::ItemFindByAccessChar() method looks like.
INT CExtPopupMenuWnd::ItemFindByAccessChar(
__EXT_MFC_SAFE_TCHAR chrAccess,
INT nStartIdx, // = -1
BOOL bRestartAt0, // = TRUE
BOOL bSearchDisplayedOnly // = TRUE
) const
{
ASSERT_VALID( this );
if( chrAccess == _T(’0’) )
return -1;
. . .
There is a typo in the if( chrAccess == _T(’0’) ) line of code. It really should be if( chrAccess == _T(’\0’) ): INT CExtPopupMenuWnd::ItemFindByAccessChar(
__EXT_MFC_SAFE_TCHAR chrAccess,
INT nStartIdx, // = -1
BOOL bRestartAt0, // = TRUE
BOOL bSearchDisplayedOnly // = TRUE
) const
{
ASSERT_VALID( this );
if( chrAccess == _T(’\0’) )
return -1;
. . .
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